笨办法学Python3 习题35
习题35 分支和函数 from sys import exit def gold_room(): print(This room is full of gold. How much do you take?) next = input(> ) if 0 in next or 1 in next: how_much = int(next) else: dead(Man, learn to type a number.) if how_much ) if next == take
下载地址
用户评论